anonanon 152k1212 gold badges233233 silver badges398398 bronze badges $endgroup$ 4 $begingroup$ Which is great thanks a bunch! I also posted an analogous question here: math.stackexchange.com/thoughts/2135276/… that you might have some Perception on? $endgroup$
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RexcirusRexcirus 43544 silver badges1515 bronze badges $endgroup$ two $begingroup$ Your final expression would not make Significantly feeling: The LHS has free indices $i,j,k$ whereas your RHS has free indices $i,j,l$. $endgroup$
I am utilizing the Einstein notation, so numerous indices are summed) or they offer two 3-indices symbols with distinct indicator
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The Levi-Civita tensor is Employed in the Einstein industry equations to express the curvature of spacetime in terms of the Strength and momentum of subject and radiation.
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The following are examples of the final identity higher than specialized to Minkowski Area (With all the destructive indication arising within the odd variety of negatives from the signature with the metric tensor in try this out possibly signal convention):
In Einstein notation, the duplication with the i index indicates the sum on i. The preceding is then denoted εijkεimn = δjmδkn − δjnδkm.
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That is the denominator on the Brier rating for joint many variables predictions? far more warm thoughts
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